Question

need explanation and steps​

Answer 1

Answer:

±$\sqrt{51}$

Step-by-step explanation:

Given, $x^2 + \frac{1}{x^2} = 53$

We know that $( a- b)^{2} = a^2 - 2ab + b^2$

Putting a =x and b = $\frac{1}{x}$ we get:

$(x - \frac{1}{x})^2 = x^2 - 2*x* \frac{1}{x} + \frac{1}{x^2}$

=> $(x - \frac{1}{x})^2 = x^2 - 2 + \frac{1}{x^2}$

=> $(x - \frac{1}{x})^2 = 53 - 2$

=> $(x - \frac{1}{x})^2 = 51$

=> $(x - \frac{1}{x}) =$ ±$\sqrt{51}$

Answer 2

Answer:

x^2+1/x^2=53

x-1/x=?

(x-1/x) ^2=(x^2+1/x^2) -2

(x-1/x) ^2=53-2

x-1/x=√51 will be the answer

Step-by-step explanation:

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