Need explanation pls
A crane machine is used to lift cement slabs of weight w at Delhi metro site. Machine have to lift the slabs from rest and have to put them on the elevated platform at a height ‘h’. If the maximum tension that the cable of crane machine can tolerate is nw (n > 1), then minimum time in which ascent can be done by the machine is (Tmin = 0)
ANS: (2nh/(n-1)g)^1/2
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Answer:
Proved
Explanation:
Net force = (n-1)w
Net acceleration = (n-1)w/m
Now h = 0.5{(n-1)w/m}t² = 0.5{(n-1)g}t²
t = {2h/(n-1)g}∧0.5
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