Math, asked by Anonymous, 10 months ago

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Answered by rasneet25
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      n(S) = 21 n(T) = 32

      n(S) = 21 n(T) = 32S ∩ T =11

      n(S) = 21 n(T) = 32S ∩ T =11S ∪ T = ?

      n(S) = 21 n(T) = 32S ∩ T =11S ∪ T = ?we know that ,

      n(S) = 21 n(T) = 32S ∩ T =11S ∪ T = ?we know that ,    

      n(S) = 21 n(T) = 32S ∩ T =11S ∪ T = ?we know that ,    S ∪ T = n(S) + n(T) - S ∩ T Substituting the values ,we get

      n(S) = 21 n(T) = 32S ∩ T =11S ∪ T = ?we know that ,    S ∪ T = n(S) + n(T) - S ∩ T Substituting the values ,we get      

      n(S) = 21 n(T) = 32S ∩ T =11S ∪ T = ?we know that ,    S ∪ T = n(S) + n(T) - S ∩ T Substituting the values ,we get      S ∪ T = n(S) + n(T) - S ∩ T                 =21 + 32 - 11 = 53 - 11 = 42

      n(S) = 21 n(T) = 32S ∩ T =11S ∪ T = ?we know that ,    S ∪ T = n(S) + n(T) - S ∩ T Substituting the values ,we get      S ∪ T = n(S) + n(T) - S ∩ T                 =21 + 32 - 11 = 53 - 11 = 42Hope this helps You!!!

Answered by Anonymous
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