Question

need help ...............

Answer 1

Let net acceleration be 19.6 - 9.8 (due to gravity) = 9.8 m/s2

By equation 1,

V = u + at
V = 0 + 9.8 * 5

V = 49 m/s

Now we know distance = speed*time

49 x 5 = 245 m

Hence max height is 245m