Question

need help !!!!!!!!!!!!!!!!!????!!!?!!!​

Answer 1

Answer:

6

Step-by-step explanation:

$x - \frac{1}{x} = 2 \\ > > {(a - b)}^{2} = {a}^{2} + {b}^{2} - 2ab < < \\ > > {a}^{2} + {b}^{2} = {(a - b)}^{2} + 2ab < < \\ {x}^{2} + \frac{1}{ {x}^{2} } = {(x - \frac{1}{x} )}^{2} + 2 \times x \times \frac{1}{x} \\ {x}^{2} + \frac{1}{ {x}^{2} } = {(2)}^{2} + 2 \\ {x}^{2} + \frac{1}{ {x}^{2} } = 4 + 2 \\ {x}^{2} + \frac{1 }{ {x}^{2} } = 6$