Math, asked by Intellectual88, 10 months ago

Need help ASAP!
Please give Step by step explanation on how to find zeros of cubic polynomial and the question above​

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Answers

Answered by tennetiraj86
11

Answer:

option is not there in your answers

answer is -9

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Answered by Tomboyish44
36

We know that for a cubic polynomial with the zeroes α, β & γ, the product of the zeroes can be written as;

\sf \Longrightarrow \alpha \ \beta \ \gamma = - \ \dfrac{Constant \ term}{Coefficient \ of \ x^3}

\sf \Longrightarrow \alpha \ \beta \ \gamma = \dfrac{-d \ \ }{a}

Where;

a → Coefficient of x³

b → Coefficient of x²

c → Coefficient of x

d → Constant term.

We have the polynomial;

p(x) = 2x³ - 25x² - 34x + 18

Here;

a = 2

b = -25

c = -34

d = 18

So, the product of zeroes of this polynomial will be;

\sf \Longrightarrow \alpha \ \beta \ \gamma = \dfrac{-d \ \ }{a}

\sf \Longrightarrow \alpha \ \beta \ \gamma = \dfrac{-18 \ \ }{2}

\sf \Longrightarrow \alpha \ \beta \ \gamma = -9

∴ Product of zeroes of the polynomial 2x³ - 25x² - 34x + 18 is -9.

(Answer isn't there in the options, there's something incorrect with the question)

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