Math, asked by sushimaster101, 8 months ago

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Answered by lodhiyal16
0

Step-by-step explanation:

let suppose that the column are labelled A,B ,C . Consider the string AAABBBCC . since the arrangement of the strings is bijective to the order of shooting , the answer is the number of ways to arrange the letters which is 8!/3!.3!.2!= 560

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