Question

need help for 13th sum guyz

Answer 1

The sum of the coefficients = 0, which means one of the solution is 1

The product of the solutions of a polynomial of the form ax²+bx+c will be $\frac{c}{a}$

In the given case $\frac{c}{a}$ = $\frac{r-p}{p-q}$

As we know one of the solution is 1 then the product of the solutions will be equal to other solution that is $\frac{r-p}{p-q}$

So sulutions are 1 and $\frac{r-p}{p-q}$