Question

need help fr Dis ques.​

Answer 1

Answer:

Ans: 0

Step-by-step explanation:

Let x/b+c-a=y/c+a-b=z/a+b-c=k

then

x=(b+c-a)k

y=(c+a-b)k

z=(a+b-c)k

Then

(b-c)x+(c-a)y+(a-b)z

=(b-c)(b+c-a)k +(c-a) (c+a-b)k + (a-b)(a+b-c)k

=k[ b²-c²-a(b-c) +c²-a²-b(c-a)+a²-b²-c(a-b) ]

=k(  b²-c²+c²-a²+a²-b²-ab+ca-bc+ab-ca+bc)

=k(0)

=0