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alonaskidmore:
i dont understand
vo x -axis pe 6 par touch kar rhi h line and vo bhi +wale pe and -3 y-axis par h so
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here the coordinates are (6,0) and (0,-3).
equation of a straight line is y=mx+c
c= y-coordinate, so here c= -3
slope (m)= y2-y1/x2-x1
= -3-0/0-6
= -3/-6
= 1/2
now the equation is y=1/2x-3.
or
x-2y-3=0.
this is the answer..
hope this helps you..
equation of a straight line is y=mx+c
c= y-coordinate, so here c= -3
slope (m)= y2-y1/x2-x1
= -3-0/0-6
= -3/-6
= 1/2
now the equation is y=1/2x-3.
or
x-2y-3=0.
this is the answer..
hope this helps you..
this is the answer...
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