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Factorize -
1. 999^2-1
2. (10.2)^ 3
3. 1002 x 998
(using factor theorem)
Answers
Answered by
10
Solution 1.)
999^2 - 1
= (999)^2 - (1)^2
= (999 + 1)(999-1)
= 1000 (998)
= 998000
Solution 2.)
(10.2)^3
= (10 + 0.2)^3
= (10)^3 + (0.2)^3 + 3(10)(0.2)(10.2)
= 1000 + 0.008 + 6 (10.2)
= 1000 + 0.008 + 61. 2
= 1061.208
Solution 3.)
1002 × 998
= (1000 + 2)(1000 - 2)
= (1000)^2 - (2)^2
= 1000000 - 4
= 999996
999^2 - 1
= (999)^2 - (1)^2
= (999 + 1)(999-1)
= 1000 (998)
= 998000
Solution 2.)
(10.2)^3
= (10 + 0.2)^3
= (10)^3 + (0.2)^3 + 3(10)(0.2)(10.2)
= 1000 + 0.008 + 6 (10.2)
= 1000 + 0.008 + 61. 2
= 1061.208
Solution 3.)
1002 × 998
= (1000 + 2)(1000 - 2)
= (1000)^2 - (2)^2
= 1000000 - 4
= 999996
Answered by
2
Solution 1.)
999^2 - 1
= (999)^2 - (1)^2
= (999 + 1)(999-1)
= 1000 (998)
= 998000
Solution 2.)
(10.2)^3
= (10 + 0.2)^3
= (10)^3 + (0.2)^3 + 3(10)(0.2)(10.2)
= 1000 + 0.008 + 6 (10.2)
= 1000 + 0.008 + 61. 2
= 1061.208
Solution 3.)
1002 × 998
= (1000 + 2)(1000 - 2)
= (1000)^2 - (2)^2
= 1000000 - 4
= 999996
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