Question

Need Help !
No Spams !!

Answer 1

★Let the Costprice of saree and sweater be x and y

_______________________________

★Given :-

★Saree is sold at 8% profit

★Sweater is sold at 10% discount

★Saree and sweater take Rs 1008

_______________________________

Now :-

★Selling price saree

= x + 8x ÷ 100 = 108x ÷ 100

_______________________________

★Selling price of sweater

= y - 10y ÷ 100 = 9y ÷ 10

_______________________________

★Given:-

=> 108x ÷ 100 + 9y ÷ 10 = 1008

=> 108x + 90y ÷ 100 = 1008

=> 108x + 90y = 100800

=> 6x + 5y = 5600

=> x = 5600 - 5y ÷ 6 ..... (Equation 1)

_______________________________

★Selling price of saree :-

= x + 10x ÷ 00 = 11x ÷ 10 (Given 10% profit)

_______________________________

★Sellingprice of sweater :-

= y - 8y ÷ 100 = 92y ÷ 100 (Given 8% discount)

= 11x ÷ 10 + 92y ÷ 100 = 1028 (Given Saree and sweater take 1028)

=> 110x + 92y ÷ 100 = 1028

=> 110x + 92y = 102800

_______________________________

★Substitute the value from equation (1)

=> 110 (5600 - 5y ÷ 6) + 92y = 102800

=> 616000 - 550y ÷ 6 + 92y = 102800

=> 616000 - 550y - 552y ÷ 6 = 102800

=> 616000 + 2y ÷ 6 = 102800

=> 616000 + 2y = 616800

=> 2y = 800

=> y = 400

_______________________________

★Now :-

x = 5600 - 5 × 400 ÷ 6

x = 5600 - 1200 ÷ 6

x = 4200 ÷ 6

=> x = 700

So we find that :-

_______________________________

★Sellingprice of saree = 700

★List price of sweater = Rs 400

_____________________________________________________________________________________________

Regards :)

Cybary

Be Brainly

Answer 2

$\bold{\large{\underline{\underline{\sf{StEp\:by\:stEp\:explanation:}}}}}$

Let the cost price of saree be Rs. 'x' and the list price of sweater be Rs. y.

Therefore,

$\bold\green{Situation 1 -}$

By selling a saree at 8 % profit and a sweater at 10 % discount, the shopkeeper gets Rs. 1008

⇒ 108x/100 + 90y/100 = 1008

⇒ 27x/25 + 9y/10 = 1008/1

Taking L.C.M. of the denominators and then solving it, we get.

54x + 45y = 50400 _________(1)

$\bold\green{Situation 2 -}$

by selling a saree at 10 % profit and a sweater at 8 % discount, the shopkeeper gets Rs. 1028.

$\sf{ \frac{110x}{100} + \frac{92y}{100} = 1028 }$

$\sf{ \frac{11x}{10} + \frac{23y}{25} = 1028}$

Taking L.C.M. of the denominators and then solving it, we get.

⇒ 55x + 46y = 51400 _______(2)

Now, multiplying the equation (1) by 55 and (2) by 54, we get.

(54x + 45y = 50400)×55

= 2970x + 2475y = 2772000 _____(3)

(55x + 46y = 51400)×54

= 2970x + 2484y = 2775600 _____(4)

Now, subtracting (3) from (4), we get.

2970x + 2484y = 2775600

2970x + 2475y = 2772000

. - - - ___________________________

. 9y = 3600

___________________________

⇒ 9y = 3600

y = 3600/9

y = 400

Putting the value of y = 400 in (1), we get.

54x + 45y = 50400

54x + (45 × 400) = 50400

54x + 18000 = 50400

54x = 50400 - 18000

54x = 32400

.

x = 600

So, the cost price of a saree is Rs. 600 and the list price of a sweater is Rs. 400