Question

need help pls send me the solution​

Answer 1

Step-by-step explanation:

$\frac{6}{ \sqrt{12} - \sqrt{3} } \\ = \frac{6}{ \sqrt{12} - \sqrt{3} } \times \frac{ \sqrt{12} + \sqrt{3} }{ \sqrt{12} + \sqrt{3} } \\ = \frac{6( \sqrt{12} + \sqrt{3} )}{ {( \sqrt{12}) }^{2} - { (\sqrt{3} )}^{2} } \\ = \frac{6( \sqrt{12} + \sqrt{3} )}{12 - 3} \\ = \frac{6((\sqrt{2 \times 2 \times 3}) + \sqrt{3}) }{9} \\ = \frac{6(2 \sqrt{3} + \sqrt{3}) }{9} \\ = \frac{2(3 \sqrt{3} )}{3} = 2 \sqrt{3}$

Answer 2

Answer:

it help

Step-by-step explanation: