need help...question no.52
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40°
Join OE
Then angle EOC = 2angleEBC = 2×50 = 100
OE = OC ( Radius of circle ) therefore Angle ECA = 40°
so angle CED = ECA (alternate interior angles )
CED = 40°
Join OE
Then angle EOC = 2angleEBC = 2×50 = 100
OE = OC ( Radius of circle ) therefore Angle ECA = 40°
so angle CED = ECA (alternate interior angles )
CED = 40°
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