Question

Need help!!! Relevant answers only...

Answer 1

${ \huge{ \boxed{ \underline{ \tt{ \color{teal}{required \: \: answer:}}}}}}$

To Solve:

• Find roots of : x² - 4ax + 3a² = 0

Solⁿ:

• Splitting term = - 4ax
• Split in : -3ax, -1ax
• x² = 1, x = -4a, c = 3a²

${x}^{2} - 4ax + 3 {a}^{2} = 0\\ \\ {x}^{2} - 3ax - 1ax + 3 {a}^{2} = 0 \\ \\ x(x - 3a) - 1a(x - 3a) = 0 \\ \\ (x - 3a)(x - 1a) = 0 \\ \\ { \boxed{ \color{teal}{ \tt{roots = \: \: \: x = 3a \: \: \: \: \: \: \: \: \: \: x = 1a}}}}$

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Hope It Helps

Mark Brainliest Pls :)