Math, asked by Anonymous, 9 months ago

need help solve it.plzz guys correct ans​

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Answered by Anonymous
17

\huge\mathfrak\color{red}{Answer}

\huge\underline\mathrm{GiVeN}

P = 6400

T = 2 years

R = 33 3/4 % = 135 / 4%

\huge\underline\mathrm{FoRmUlA}

a  = p(1 +  \frac{r}{100} ) {}^{n}

\huge\underline\mathrm{SoLuTiOn}

a  = p(1 +  \frac{r}{100} ) {}^{n}

a = 6400 \times (1 +  \frac{ \frac{135}{4} }{100} ) {}^{2}

a = 6400 \times( 1 +  \frac{135}{4}  \times  \frac{1}{100}  \times 2) {}^{2}

a = 6400 \times (1 +  \frac{27}{40} ) {}^{2}

a = 6400 \times ( \frac{67}{40} ) {}^{2}

a = 6400 \times  \frac{4489}{1600}

a = 17956

Amount = 17956

C.I. = Amount - P

ci = 17956 - 6400

ci = 11556

hope it helps you.....

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