Question

NEED HELP!!!!!
The polynomial x^3-mx^2+4x+6 when divided by (x+2) leaves remainder 14 find the value of m.
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Answer 1

put
$x = - 2 \: in \: polynomial \: and \: equate \: to \: 14 \\ ( { - 2)}^{3} - m( - {2)}^{2} + 4( - 2) + 6 = 14 \\ - 8 - 4m - 8 + 6 = 14 \\ - 4m = 14 + 10 \\ - 4m = 24 \\ m = \frac{ - 24}{4} \\ m = - 6 \: \: \: answer$