Math, asked by sreshub, 1 day ago

need help with this maths geomtery question also message if you can help me with my exams

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Answered by nilanjan321

Answer:

detailed answers are shown step by step for the geometry questions given in the PDF

Step-by-step explanation:

1. i) the sum of three inside angles generated by a triangle is = 180 degree.

So, <ABC + <BCA + <CAB= 180degree

Now, as AB=AC, <ABC will be equals to <ACB. You already know <BAC =55 degree.

So, <ABC + <BCA + <CAB =180 degree

<ABC + <BCA + 55 degree =180 degree

<ABC + <BCA =180 degree - 55 degree

<ABC + <BCA =125 degree

Now, as <ABC = <BCA thus, <ABC = <BCA = = 62.5 degree

1. ii) As, QP=PR, <PQR will be = <PRQ

<PQR = <PRQ = 72 degree

<QPR = 180- ( 2 x 72 degree) = 36 degree

2.i) as, AB=AC, <Y =52 Degree

<Z = 180-(52 x 2)= 76degree

<X = 180- 52 = 128 degree

2.ii) <x = 66 degree as both are Contrast angle.

FE=EZ. So, <y= =57 degree

<z = 180-57 = 123 degree

2.iii) AB=BC, So, <x = 180-(70 x 2)= 40 degree

<z = 180-70= 110 degree

AC=AC, So, <y= = 35 degree

2.iv) MP=PL. So, <x= 180-(35 x 2 )=110

MP=PL=PN. now, <LPN= 180-110=70 degree

So, <y= =55 degree

<z= 180-55= 125 degree

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