Question

need only correct answers

Answer 1

$289 = { \big(17 \big)}^{ \frac{x}{5} } \\ \\ {17}^{2} = { \big(17 \big)}^{ \frac{x}{5} } \\ \\ 2 = \frac{x}{5} \\ \\ x = 2 \times 5 \\ \\ \boxed{ \red{x = 10}}$

Answer 2

The value of x is 10.....................