Question

Need Quality Answer.

Don't Spam ❌❌❌​

Answer 1

❍ Solution ❍

• $At \: the \: time \: of \: dropping, \: the \: velocity \: \\ of \: the \: bolt \: relative \: to \: the \: floor \: of \: \\ the \: elevator \: = 0.$

• $The \: acceleration \: of \: the \: bolt \: \\ relative \: to \: the \: floor \: of \: the \: \\ elevator = 9.8 - ( - 0.2) = 10m/s {}^{2} \\ downwards.$

Let the time taken by the bolt to reach the floor be there seconds.

Then,

$S = ut + \frac{1}{2} a \: t {}^{2} \\ = > 2.5 = 0 + \frac{1}{2} \times 10 \times t {}^{2} \: or \: t {}^{2} = \frac{1}{2}$

$= > t = \sqrt{0.5} = 0.713$

The bolt takes 0.713 to reach the floor of the elevator. During this time the actual distance travelled down by the bolt.

$= 2t - \frac{1}{2} \times 9.8 \times t {}^{2} \\ (2 \: m/s \: is \: the \: initial \: upward \: velocity \: \\ of \: the \: bolt).$

$= 2 \times 0.71 - 4.9 \times (0.71) {}^{2}$

$= 1.42 - 4.9 \times 0.5 = 1.42 - 2.45 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - 1.03m$

• ∴ The distance travelled downwards by the bolt = 1.03m.

Explanation:

$@PopularANSWERER }$

Answer 2

Answer:

Refer above attachment for the answer

Explanation:

@ANSWERER