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Answer:
r = 20√(5/2) m
r = 20√(5/2)Explanation:
F = Gm(1)m(2) ÷ r²
according to question
F(1) = 2 F(2)
=> G(40)(60) ÷ (20²) = 2×G(60)(50)÷ (r²)
=> r² = 2× (60)(50) ×(20²) ÷ { (40)(60)}
=> r² = (2×50/40) (20²)
=> r² = (100/40) (20²)
=> r = √(5/2) ×√(20²)
=> r = 20√(5/2) m
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