Math, asked by kinjal74, 11 months ago

need sloution of dis one​

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Answered by ishita353
2

cos2x = 1-2sin²x

sin²x = (1-cos2x)/2

here, x=45°/2

sin²45°/2= (1-cos45°)/2

= (1-1/√2)/2

=(√2-1)/2√2

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