Question

need solution!!

Trigonometry​

Answer 1

Answer:

Step-by-step explanation:

Given :

A expression

$x^{2}+y^{2}=xy$--------------------------(1)

To Find :

A value of x,y for point (x,y) which satisfy the expression

Solution:

we know that

$\sin ^{2}\Theta + \cos ^{2}\Theta =1$

Dividing bot sides by $\sin ^{2}\Theta \cos ^{2}\Theta$

⇒ $\frac{\sin ^{2}\Theta}{ \sin ^{2}\Theta \cos ^{2}\Theta }+ \frac{\cos ^{2}\Theta}{ \sin ^{2}\Theta \cos ^{2}\Theta } =\frac{1}{\sin ^{2}\Theta \cos ^{2}\Theta \\}$

⇒  $\frac{1}{\sin ^{2}\Theta }\ +\frac{1}{\cos ^{2}\Theta }\ =\sec ^{2}\Theta \mathrm{cosec} \cosec ^{2}\Theta$

⇒  ${\sec ^{2}\Theta }\ + \mathrm{cosec} ^{2}\Theta ={\sec ^{2}\Theta }\ \mathrm{cosec} ^{2}\Theta$

This is similar to the the given expression(1)

Hence Point is ($({\sec \Theta }\ , \mathrm{cosec} \Theta)$

Option (c) is correct

Concepts used:

$\sin ^{2}\Theta + \cos ^{2}\Theta =1$

Other useful concepts:

1. Important: I heard that some students get afraid by listen name of theta ($\theta$) .
2. But nothing to worry this ($\theta$) is just like a,b,c,x,y,z which we use in maths.
3. We can take any letter in place of ($\theta$) like A,p,B,n etc.
4. Entire trigonometry is same to other maths sections.