Question

need step by step answer. I'll mark as brainliest​

Answer 1

Given,

CD || AB

→ CD || AF (shown in the given diagram),

Let zx and <DCE are linear pairs,

→ 4x + mzDCE= 180°,

→ LX + 75° = 180°

(by the diagram),

→ 4x = 180° - 75° = 105°, By the alternate interior angle theorem,

→ mzx= mz1

→ mz1 = 105⁰,

Now, by the vertically opposite angle theorem,

Z1= LBEO,

→ mzBEO = 105°,

Now, mzEBO = 15°,

BEO is a triangle,

→ mzEBO + mzBEO + mzBOE = 180°,

→ 15° +105° + mzBOE = 180°,

→ 120° + mzBOE = 180°,

→ mzBOE = 60°,

Answer 2

Sorry dii I don't know but FOLLO.W me