Math, asked by srinithiahvar03, 11 months ago

need step by step explanation
give u brainliest
100points​

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Answered by suchindraraut17
0

x=\frac{ac}{c+b}

Step-by-step explanation:

Let the given traingle be named by ΔABC for big triangle,while small triangle be named as Δ ADE.

Now,In ΔABC and in ΔADE,

∠A=∠A [Common]

∠AED=∠ACB [Given]

So,By AA similarity ΔABC and ΔADE are similar.

Now,\frac{AE}{DE}=\frac{AC}{BC}

      \frac{AE}{DE }=\frac{AE+EB}{BC}

       ⇒\frac{c}{x}=\frac{c+b}{a} [From given figure]

     ⇒\frac{c}{c+b}=\frac{x}{a}

    ⇒ \frac{ca}{c+b}=x

     ⇒ x=\frac{ac}{a+b}

Answered by Abhis506
0

Step-by-step explanation:

Let the given traingle be named by ΔABC for big triangle,while small triangle be named as Δ ADE.

Now,In ΔABC and in ΔADE,

∠A=∠A [Common]

∠AED=∠ACB [Given]

So,By AA similarity ΔABC and ΔADE are similar.

Now,\frac{AE}{DE}=\frac{AC}{BC}</p><p>      \frac{AE}{DE }=\frac{AE+EB}{BC}</p><p>       ⇒\frac{c}{x}=\frac{c+b}{a} [From given figure]</p><p>     ⇒\frac{c}{c+b}=\frac{x}{a}</p><p>    ⇒ \frac{ca}{c+b}=x</p><p>     ⇒ x=\frac{ac}{a+b}

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