Question

Need the answer asap

Answer 1

Step-by-step explanation:

1.QR²= 24²+10²=576+100=676 (By phythagoras theorem)

QR=26cm

2. let girls be X

X+X+11=75

2X=64

X=32

No of boys = 43

No of girls=32

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Answer 2

$\red{ \large{ \sf{ \underline{ \underline{Solution \: of \: Q.1}}}}}$

$\sf{ \purple{ \underline{Given}}}$

$\sf{In \: triangle \: PQR, }$

$\sf{ \angle{P = 90}}$

$\sf{PQ = 10cm \: and \: PR = 24cm}$

$\sf{so \: QR = }$

$\sf{ \blue{From \: Pythagoras \: theorem}}$

$\bf{ \purple{ \boxed{(Hypotenuse) {}^{2} = Prependicular {}^{2} + Base {}^{2} }}}$

$\sf{QR { }^{2} = PQ {}^{2} + PR {}^{2} }$

$\sf{QR {}^{2} = 10 {}^{2} + 24 {}^{2} }$

$\sf{QR {}^{2} = 676}$

$\sf{QR = \sqrt{676} = 26}$

$\sf{ \underline{ \green{Hence \: QR = 26cm}}}$

$\red{ \large{ \sf{ \underline{ \underline{Solution \: of \: Q.2}}}}}$

$\sf{ \purple{ \underline{Given}}}$

$\sf{The \: number \: of \: boys \: is \: 11 \: more \: than \: the \: number \: of \: girls}$

$\sf{The \: common \: number \: of \: boys \: and \: girls \: are = 75 - 11 = 64}$

$\sf{ The \: number \: of \: girls = \frac{64}{2} = 32}$

$\sf{Now, \: The \: number \: of \: boys = 32 + 11 = 43}$

$\sf{ \underline{ \green{Hence, \: the \: number \: of \: girls \: are \: 32 \: and \: boys \: are \: 43}}}$

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