Question

need the answer to the question with explanation

Answer 1

Given:

Mass of Bullet= 10g= 0.01kg

Initial velocity= 0m/s

Final velocity= 20m/s

Time taken= 10s

To Find:

• Power developed by the bullet during the time

Solution:

We know that,

• First equation of motion

⟼ v= u+at

• Force= mass × acceleration

• Power= Force × Velocity

Now,

Using first equation of motion,

⇒ 20= 0+a(10)

⇒ 10a= 20

⇒ a= 2 m/s²

Now,

Force of bullet,

⇒ F= ma

⇒ F= 0.01×2

⇒ F= 0.02N

Now,

⇒ Power= Fv

⇒ Power= 0.02×20

⇒ Power= 0.4 W

Hence, the power developed by the bullet during the time is 0.4W

Answer 2

0. 4 W

Explanation:

Solution : Given that

Mass of bullet(m) =10g

=10/1000 kg

=. 01 Kg

Velocity of bullet (V) =20m/s

Time taken (t) =10 s

initial velocity (u) =0m/s

As we know that v=u +at

20 =0+a ×10

20=a×10

a=20/10

a=2 m/s^2

Force produced by the bullet (F) =mass×acceleration

F=m×a

=. 01 ×2

=.02 N

Also, we know that

POWER =work done /time

P=W/t - - -( i)

Work done (W) =Force(F) ×Displacement (S)

W= F× S

Now from equation (i)

P=F×S/t

P=F × v (as V =S/t)

P=. 02×20

=. 4 W

POWER developed by the bullet. =. 4 W