Question

Need the answer with explanation

Answer 1

Answer:

I will not seen clearly so iam sorry

Answer 2

Answer:

i hope its right

Step-by-step explanation:

(x a2/x b2)1/a+b × (x b2/x c2)1/b+c × (x c2 /x a2)1/a+b = 1 [ that is the ques] (2 as a square ok)

answer : first (cut all x, becaz x/x = 1 )

(a2/a+b ÷ b2/a+b ) × (b2 /b+c ÷ c2 /b+c ) × (c2 /c+a ÷ a2/ c+a ) = 1 , that will be :

let (a+b )= x , (b+c) = y , (c+a) = z

[a2 (x)/b2 (x) ] × [b2 (y) /c2 (y) ]×c2 (z)/ a2(z)

= 1

cut all x, y and z (x/x = 1 ,y/y= 1 and z/z = 1)

a2 / b2 × b2 / c2 × c2 / a2 = 1

(a2 ×b2× c2) ÷ (b2 ×c2 ×a2) = 1

(a2 / a2 =1) × ( b2/b2 =1 ) × (c2 / c2 = 1) = 1

1× 1× 1 = 1

1 = 1

# solved