Question

Need to know quickly...

Answer 1

Step-by-step explanation:

let 3x+3 be angle 1

let 4x+2 be angle 2

angle1+angle2=180° (linear pair)

3x+3+4x+2=180°

7x+5=180°

7x=175

x=175/7

x=35

now 3x+3=108°

and 4x+2=142°

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Answer 2

Step-by-step explanation:

Here,

∠ACD = ∠BCD [ ∵ ∠ACD and ∠BCD form a linear pair ]

BTP,

∠ACD = ∠BCD

$⟹ {(3x + 3)}^{°} + {(4x + 2)}^{°} = 180° \\ ⟹3x + 4x + 2 + 3 = 180 \\ ⟹ 7x = 180 - 5 \\ ⟹ x = 25$

SO,

the value of x is 25.

Hence,

∠ACD = (3x + 3)° = (3×25 + 3)° = 78°

∠BCD = (4x + 2)° = (4×25 + 2)° = 102°