Need to prove that angle BOC = 90° - 1/2 angle A
Answers
Answered by
7
ItzJanhvi 10❤
Attachments:

Answered by
8
Step-by-step explanation:
∠1=∠2,∠4=∠5
∠1=∠2,∠4=∠5In ΔABC
∠1=∠2,∠4=∠5In ΔABC∠A+∠B+∠C=180
∠1=∠2,∠4=∠5In ΔABC∠A+∠B+∠C=180∠A+2∠2+2∠5=180
∠1=∠2,∠4=∠5In ΔABC∠A+∠B+∠C=180∠A+2∠2+2∠5=180∠2+∠5=90−21∠A
∠1=∠2,∠4=∠5In ΔABC∠A+∠B+∠C=180∠A+2∠2+2∠5=180∠2+∠5=90−21∠ANow in ΔBOC
∠1=∠2,∠4=∠5In ΔABC∠A+∠B+∠C=180∠A+2∠2+2∠5=180∠2+∠5=90−21∠ANow in ΔBOC∠2+∠5+∠BOC=180
∠1=∠2,∠4=∠5In ΔABC∠A+∠B+∠C=180∠A+2∠2+2∠5=180∠2+∠5=90−21∠ANow in ΔBOC∠2+∠5+∠BOC=18090−21∠A+BOC=180
∠1=∠2,∠4=∠5In ΔABC∠A+∠B+∠C=180∠A+2∠2+2∠5=180∠2+∠5=90−21∠ANow in ΔBOC∠2+∠5+∠BOC=18090−21∠A+BOC=180∠BOC=90+21∠A
∠1=∠2,∠4=∠5In ΔABC∠A+∠B+∠C=180∠A+2∠2+2∠5=180∠2+∠5=90−21∠ANow in ΔBOC∠2+∠5+∠BOC=18090−21∠A+BOC=180∠BOC=90+21∠A∠BOC=90+21∠BAC
Hope this will help you.
Similar questions