Question

NEED URGENT ANSWER ....A wire is bent in the form of a circle with radius 49 cm, it is straightened and made into a square, then the length of the side of the square is (A) 11 cm (B) 77 cm (C) 38.5 cm (D) 22 cm​

Answer 1

Answer:

Let the side of the square be a cm

Thus, perimeter is 4a and area of the square is a

2

∴a

2

=81

⇒a=

81

⇒a=9

Thus, perimeter =4×9 =36 cm

Now, wire is bent into a semicircle.

Therefore, 2r+πr=36

⇒r(π+2)=36 $$

⇒r=

7

22

+2

36

⇒r=

7

36

36

⇒r=7 cm

Area of semicircle =

2

1

πr

2

=

2

1

×

7

22

×7×7

=77 cm

2

Step-by-step explanation:

hope that help you

Answer 2

Answer:

a

Step-by-step explanation:hope it helps you Pls mark me as brainlest