Question

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4. The top of ladder of lengthy 15m reaches a window 9 m above the ground . What is the distance between the base of the wall and that of the ladder?​

Answer 1

Answer:

In the right-angled triangle LMN, ∠M = 90°. Hence, side LN is the hypotenuse. ∴ Length of seg MN = 16 m. Hence, the distance between the base of the wall and that of the ladder is 12 m.

Step-by-step explanation:

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Answer 2

Given:

∆ ABC and ∠B = 90°

To Find:

The distance between the base of the wall and that of the ladder.

.•♫•♬•Solution •♬•♫•.

By Using Pythagoras theorem

$= > AC {}^{2} = AB {}^{2} + BC {}^{2}$

$= > 15 {}^{2} = 9 {}^{2} + BC$

$= > 225 = 81 + BC$

$= > 225 - 81 = BC {}^{2}$

$= > 144 = BC {}^{2}$

$= > \sqrt{144} = BC$

$= > BC = 12$

Hence, The the distance between the base of the wall and that of the ladder 12