Question

needed a full solution of questions no. 1

Answer 1

I hope this may help u

Answer 2

Let the height of the two trees AB and CD be b and a respectively.
Distance between the trees BC = p
Let EF = h be the height of point of intersection of the lines joining the top of each tree to the foot of the opposite trees.
Let CF = x then BF = (p – x)
In Δ’s ABC  and EFC,
∠ABC = ∠EFC = 90°
∠C = ∠C (common angle)
∴ ΔABC ~ ΔEFC (By AA similarity theorem)
→ b/p = h/x
→ bx = ph
→ x = ph/d
Similarly, ΔDCB ~ ΔEFB (By AA similarity theorem)
→ a/p = h/(p-x)
→ ap-ax = ph
→ ap-a(ph/b) = ph
→ p[a-(ah/b) = ph
→ (ab-ah)/b = h
→ ab-ah = bh
→ ab = ah+bh = h(a+b)
→ h = ab/a+b