Math, asked by Anonymous, 9 months ago

Needed full explanation ​

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Answered by Anonymous
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Answered by Anonymous
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\huge\red{\underbrace{\overbrace{\ulcorner{\mid{\overline{\underline{ANSWER}}}}}}}

{\bf{\green{Given, }}}

{\bf{\red{n(x)=40}}}

{\bf{\blue{n(XUY)=60}}}

{\bf{\pink{n(X∩Y)=10}}}

WKT,

{\bf{\green{n(XUY)=}}}{\bf{\orange{n(X) +n(Y) ) }}}{\bf{\blue{- n(X∩Y) }}}

{\bf{\red{=>60=40+n(Y)-10}}}

{\bf{\green{=>60=30+n(Y)}}}

{\bf{\pink{=>n(Y)=60-30}}}

{\bf{\blue{=>n(Y)=30}}}

{\bf{\red{so}}}{\bf{\blue{the}}}{\bf{\pink{element}}}{\bf{\green{Y}}}{\bf{\orange{has}}}{\bf{\blue{30}}}{\bf{\red{elements}}}

{\bf{\green{FOLLOW ME}}}

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