Question

Neel is four times as old as his younger brother. The sum of their present age is 25. what is the present age of Neel and his brother​

Answer 1

Answer :

• Neel's age - 20 years.
• His brother's age - 4 years.

Explanation :

If we assume Neel's younger brother's age as ‘x’years.

∴ Neel's age - ‘4x’ years.

According to the question :

→ 4x + x = 25

→ 5x = 25

→ x = 25/5

→ x = 5

∴ Younger brother's age - 5 years.

Hence, Neel's age - 4x = 4(5) = 20 years.

Answer 2

Answer:

Given:-

• Neel's age is four times as old as his younger brother.

To Find:-

• The age of Neel and his younger brother?

Solution:-

Let the age of Neel's brother = 'x'

Then, the age of Neel = '4x'

According to the question:-

$(4x) + (x) = 25 \\ \\ (5x) = 25 \\ \\ x = \frac{25}{5} \\ \\ x = 5$

$\dag{\boxed{ \underline{ \tt{ \red{age \: of \: Neel's \: bother = 5 \: year}}}}}$

$\dag{ \boxed{ \underline{ \tt{ \blue{age \: of \: Neel = 5x4 = 20 \: years}}}}}$

Hence, the age of Neel is 20 years and the age of Neel's brother is 5 years.