Question

neeraj goes 10 m due east and then 30 m due north the distance of neeraj from the starting point is​

Answer 1

Answer:

join all 3 points to get a right angle triangle

using pythagoras theorem

30^2 + 10^2 = dist. from starting point^2

400 = dist. from starting point^2

dist. from starting point = 20

hope it helped..