Question

Neeraj lent Rs.65536 for 2 years at 12 1/2 % per annum compounded annually . How much more could he earn if the interests were compounded half years?

Answer 1

Answer:

$\it\huge\mathfrak\red{Hello .........!}$

∴ We know that A = P(1+r/100)^n

                          = ₹65536(1+25/200)^2

                          = ₹82944.(Annually)

∴ We know that A = P(1+r/100)^n

                          =₹ 65536(1+25/400)^4

                          = ₹65536(425/400)^4

                          = ₹83521.

∴The amount he earns = ₹83521 - ₹82944

                                     =₹ 577.

$[tex]\it\huge\redmathfrak{{ Be Brainly}}$[/tex]

Answer 2

HEY MATE!!

A = P(1+r/100)^n

                    = ₹65536(1+25/200)^2

                    = ₹82944.(Annually)

A = P(1+r/100)^n

                    =₹ 65536(1+25/400)^4

                    = ₹65536(425/400)^4

                    = ₹83521.

∴The amount he earns = ₹83521 - ₹82944

                                     =₹ 577.

HOPE IT HELPS YOU!!!