Question

NEET & AIIMS
The angular position of a particle revolving about an
axis is given by e(t) = f2 - 3t + 4 radian. Find the
acceleration of the point at time t = 2 s. Given
radius of circular path is 1 m.
(1) 2 m/s2
(2) 1 m/s2
(3) 5 m/s2
(4) V5 m/s2​

Answer 1

Answer:

Explanation:

we know,

w= dtheta /dt (w=omega)

Here,

w= dtheta/dt= 2t-3

At t=2s

w=2×2-3=1

alpha = w^2 .r

Putting values ,

alpha= 1m/s^2 (b)