Neeta sold two articles at rs. 840 each. On one she gains 20% and on the other she losses 20%. How much does she gain or loss in the whole transaction ? Also find his gain or loss % in the whole transaction .
Answers
Step-by-step explanation:
sp of two articles=2×840=rs.1680.
on 1st article she gains 20%
therefore, CP of 1st article=100/(100+gain%)×840
=100/120×840
=100×7
=700.
while on 2nd article, she losses 20%
therefore, CP of 2nd article =100/(100-loss%)×840
=100/80×840
=1050.
Therefore total CP of two articles
=700+1050
=1750
since, CP>SP
Loss=1750-1680
=70
Therefore, loss%=loss/CP ×100
=70/1680×100
=41.66%.
Answer:
S.P od article = Rs 840
Let the C.P of article = x
Loss% = 20%
C.P>S.P = loss
C.P-S.P=loss
x-840=loss
Loss% = loss/C.P * 100
20% = x-840/x* 100
20*x/100 = x-840
x/5 = x-840
840=x-x/5
840= 4x/5
C.P = x = Rs 1,050
S.P of other article = Rs 840
C.P = x (let)
S.P>C.P=gain
S.P-C.P= gain
840-x= gain
Gain%=gain/C.P *100
20%=840-x/x*100
20x/100= 840-x
x/5+x= 840
6x/5 = 840
x = 700 C.P
Total S.P = 840+840= Rs 1680
Total C.P = 1050+700= Rs 1750
Overall loss because C.P>S.P
By Rs1750 - Rs 1680 =Rs 70
Step-by-step explanation: