neeta wants to lace 2 round of circular surface of the table measuring 12m. how much lace will be required
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Answered by
6
______Heyy Buddy ❤________
_____Here's your Answer ______
Diameter = 12m
=> Radius = 6m.
Now,
Circumference of the table
=> 2 × 22/7 × 6
=> 12 × 3.14
=> 37.68 m.
For 2 Rounds
=> 2 × 37.68
=> 75.36 m.
✔✔✔
_____Here's your Answer ______
Diameter = 12m
=> Radius = 6m.
Now,
Circumference of the table
=> 2 × 22/7 × 6
=> 12 × 3.14
=> 37.68 m.
For 2 Rounds
=> 2 × 37.68
=> 75.36 m.
✔✔✔
Answered by
0
Diameter = 12m
=> Radius = 6m.
Now,
Circumference of the table
= > 2 \times \pi \times r=>2×π×r
=> 2 × 22/7 × 6
=> 12 × 3.14
=> 37.68 m.
For 2 Rounds
=> 2 × 37.68
=> 75.36 m.
=> Radius = 6m.
Now,
Circumference of the table
= > 2 \times \pi \times r=>2×π×r
=> 2 × 22/7 × 6
=> 12 × 3.14
=> 37.68 m.
For 2 Rounds
=> 2 × 37.68
=> 75.36 m.
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