Question

Neeta wants to put a mirror on a wall whose length is 36.5 cm and breadth is 15 cm. How much will she spent on it if the cost of the mirror is rupees 1 per sq.cm.?​

Answer 1

Given:

• length of mirror= 36.5cm
• breadth= 15cm
• cost of mirror= 1per sq. cm

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Find:

• How much she'll spent on it?

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Solution:

Area=Length × Breadth

=> 36.5 × 15 ${cm}^{2}$

=> 547.5 ${cm}^{2}$

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${1cm}^{2}$ costs--- Rs 1

then

547.5${cm}^{2}$ will cost

= 1 × 547.5Rs.

= 547.5 Rs

$\red{\boxed{\boxed{Cost= Rs.547.5}}}$

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More formulas:-

•Area of a square= side× side

•Area of rhombus =(1/2)×d1×d2

•Area of a trapizium = (1/2)×height×(sum of length of parallel sides)

Answer 2

$\huge\underline\mathbb {SOLUTION:-}$

Answer:

• Total cost of mirror needed is ₹ 547.50.

Given:

• Length of the mirror = 36.5 cm
• Breadth of the mirror = 15 cm

Need To Find:

• The cost of the mirror is rupees 1 per sq.cm.?

Explanation:

Here, we will find the area of the mirror.

Length of the mirror = 36.5 cm

Breadth of the mirror = 15 cm

• Area of mirror = L × B

$:\implies \mathsf {36.5\:Cm \times 15\:Cm}$

$:\implies \mathsf \green {547.5\:Cm^2}$

$\underline \mathsf \orange {Now\: :-}$

Cost of one sq. cm mirror = ₹ 1

Cost of 547.5 sq. cm mirror = ₹ 1 × 547.5

$:\implies \mathsf \green {Rs.\:547.50}$

• Hence, total cost of mirror needed is ₹ 547.50.

$\underline \mathsf \orange {Here\: :-}$

• L is used for Length.
• B is uses for Breadth.

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$