Question

Neha and Nisha are playing balut game with two dice. Each has her own dice .two different dice are thrown together find the probability of the no. obtained:1. even sum. 2. even product.​

Answer 1

Step-by-step explanation:

P (even sum) =I 18 / 36 = 1 / 2

P(even product ) = 27 / 36 = 3 / 4

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Answer 2

(1) Probability of getting even sum = $\frac{1}{2}$

(2) probability getting even product = $\frac{3}{4}$

Step-by-step explanation:

Given Data

Neha and Nisha are playing with two dice.

To find the probability of getting (1) even sum (2) even sum

The probability is defined as the ratio between number of possibilities and total number of outcome.

                                              $P(A)=\frac{n(A)}{n(S)}$

Where n(S) = 36 (when two dice are thrown simultaneously)

(1) Getting even sum

The terms which gives even sums are, (1,1), (1,3),(1,5),(2,2), (2,4), (2,6),(3,1),(3,3),(3,5),(4,2),(4,4),(4,6),(5,1),(5,3),(5,5),(6,2),(6,3) and(6,6)

The number of terms which gives even number are 18

                                          n(A) = 18

The probability of getting even sum ,  $P(A)=\frac{18}{36}$

                                                               $P(A)=\frac{1}{2}$

(2) Getting even product

The terms which gives even product are (1,2), (1,4),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,2),(3,4),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,2),(5,4),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5) and (6,6)

The number of terms which gives even product are 27

                                            n(B) = 27

The probability of getting even Product is, $P(B)=\frac{27}{36}$

                                                                       $P(B)=\frac{3}{4}$

Therefore the probability of getting even sum is $\frac{1}{2}$ and the probability of getting even product is $\frac{3}{4}$ , when two dice are thrown simultaneously.

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