Question

Neha borrowed 6400 at 12% and paid 2304, as period. simple interest. Find the time period Please solve it ​

Answer 1

★ Given :-

• Principal = Rs. 6400
• Rate = 12 %
• Simple Interest Paid = Rs. 2304

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★ To Find :-

• Time Period = ?

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★ Solution :-

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∓ Here, it is given that, Principal is Rs. 6400 . Rate of Interest is 12 % . Simple Interest Paid is ₹ 2304 . And, we have to find the Time Period .

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• Now, let's solve step by step -----

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$\bull \: \sf \pmb{Simple \: Interest = \frac{P \times R \times T}{100} } \\ \\ \dashrightarrow \: \sf{2304 = \frac{6400 \times 12 \times T}{100} } \\ \\ \dashrightarrow \: \sf{2304 = \frac{64 \times 12 \times T }{1} } \\ \\ \dashrightarrow \: \sf{2304 = 64 \times 12 \times T } \\ \\ \dashrightarrow \: \sf{2304 = 768 \times T} \\ \\ \dashrightarrow \: \sf{T = \frac{2304}{768} } \\ \\ \dashrightarrow \: \sf \pmb{T = 3 \: years}$

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★ Hence :-

• Time Period = 3 years .

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