Question

Neha has a weight of 500N and tries to balance a man of weight 900 N sitting 100 cm far from the pivot of a see saw. At what distance from the pivot should Neha sit?
Plz give basic answer​

Answer 1

Answer:

Force exerted by the women = Her weight = 500N

Area on which force acts =1cm2=(1001m)2

=100001m2

∴Pressure=AreaForce=100001m2500N

=500×10000Nm−2=5×106Nm−2.

Answer 2

Answer:

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