Question

Neha invested Red. 10000 in a bank for 3years at the rate of 10.P.c.p.a she worked out the amount how many Rs she will receivr after the period ND also find Compound interest .​

Answer 1

Answer:

✦The amount she will receive the period as follows :

Here, P =10,000 R= 10 p. c.p.a, N= 3years.

❖Simple interest in the first year I =

$\frac{p \times r \times n}{100} \\ = \frac{10000 \times 10 \times 1}{100} \\ 1000$

Simple interes5 in the first year = Rs 1000.

❖Amount at the end of the year = principal + intrest

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 10,000 + 1,000

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 11,000

❖The amount at the end at the is principal for the second year.

Simple interest for the second year = I =

$\frac{11000 \times 10 \times 1}{100 } \\ = 1100$

Simple intrest for the second year = Rs 1100

❖Amount at the end of the second year = P +I

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 11000+1100

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 12,100

❖Amount at the end of the second year is the principal for the third year.

simple intrest for the third year = I =

$\frac{12100 \times 1 \times 1}{100} \\ = 1210$

simple interest for the third year = Rs 1210

❖simple interest for the third year= 12100+1210

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀= 13310.

➥Thus, at the end of the period, Neha will get Rs 13310.

When calculating simple intrest, the principal remains the same for the entire period. But, in example The above the interest of the first year is added to the principal and thus amount becomes the principal for the second year. Again the interest for the second year is added to the principal of that year and this amount becomes the principal of the third year. Interest charged in this way is called Compound intrest.

calculating compound interest by the above is tedious. The task is made easier by using the formula given below.

A= P [ 1+R/100]^N

Here, A =Amount calculated at compound interest

Compound intrest = Amount - principal

In the above, 13,310 -10,000 = Ra 3,310 is the compound intrest.

Now, let us solve the same example using the formula

Here, P= 10,000 R = 10% N= 3years

【Formula , A = p [1+R/100]^N】

⠀⠀⠀⠀⠀⠀= 10,000 [ 1+1/100]^3

⠀⠀⠀⠀⠀⠀= 10,000 [ 1+1/10]^3

⠀⠀⠀⠀⠀⠀= 10,000 [ 11/10]^3

⠀⠀⠀⠀⠀⠀= 10,000*11/10*11/10*11/10

⠀⠀⠀⠀⠀⠀= 10* 1331

⠀⠀⠀⠀⠀⠀= 13,310⠀⠀⠀

Thus Neha will get Rs 13,310. at the end of the period .

Here, 13310 - 10000 = Rs 3310 is the compound intrest.

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Answer 2

Step-by-step explanation:

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A=p[(1+R/100)ⁿ]

A=10000[1+1/100³]

A=10000[11/100³]

A=10000×11/100×11/100×11/100

A=10×1331

A=13310

C.I=13310-10000

=3310

Hope it will help you

@ Sweety Adihya

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