Question

Neha is a twice as old as Sneha five years ago his age was three times Sneha age find their present age​

Answer 1

Question :

Neha is a twice as old as Sneha five years ago his age was three times Sneha age find their present age

Solution :

let age of Neha be x

And age of Sneha be y

But we are given neha is twice as old as sneha

then according to question

x=2y−−−(1)

And after five years ago their age will be

x−5=3(y−5)

x−5=3y−15

x−3y+10=0−−−(2)

By using eq(1)

2y−3y+10=0

y=10

So , x=20

∴ age of Neha is 20 and age of Sneha is 10

More to know :

• An equations of the form Ax + By + C = 0 is called a linear equation in two variables x and y where A, B, C are real numbers.

• Two linear equations in the same two variables are called a pair of linear equations in two variables

• There are three types of systems of linear equations in two variables, and three types of solutions. An independent system has exactly one solution pair

• The point where the two lines intersect is the only solution. An inconsistent system has no solution.