Question

Neha is doing a designing course. She is working on cartesian art nowadays. For it she wants to take x coordinate from set A={0,1,2,3,5} and y coordinate from the set B={-3,-2,-1,0,1,2,3}Q1.If a relation from A to B is defined as R= {(A,B): aQ2.How many total relations can be defined from the set A to set BQ3.How many ordered pairs Neha can make from A to BQ4.How many ordered pairs Neha can make from B to A

Answer 1

Given :  she wants to take x-coordinate from the set A = {0, 1, 2, 3, 5} and y-coordinate from set B = {–3, –2, –1, 0, 1, 2, 3}.

To Find :  How many ordered pairs Neha can make from A to B

Solution:

set A = {0, 1, 2, 3, 5}

=> n(A) = 5

set B = {–3, –2, –1, 0, 1, 2, 3}.

=> n(B) = 7

ordered pairs = n(A) * n(B)

= 5 ( 7 )

= 35

35  ordered pairs

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Answer 2

SOLUTION

GIVEN

Neha is doing a designing course. She is working on cartesian art nowadays. For it she wants to take x coordinate from set A = {0,1,2,3,5} and y coordinate from the set B = {-3,-2,-1,0,1,2,3}

TO DETERMINE

1. The total relations can be defined from the set A to set B

2. The number of ordered pairs Neha can make from A to B

3. The number of ordered pairs Neha can make from B to A

EVALUATION

Here the given two sets are

A = {0,1,2,3,5}

B = {-3,-2,-1,0,1,2,3}

1. We observe that

The number of elements in A = n(A) = 5

The number of elements in B = n(B) = 7

The total relations can be defined from the set A to set B

= Total number of subsets of A × B

$\sf = {2}^{n(A) \times n(B)}$

$\sf = {2}^{5 \times 7}$

$\sf = {2}^{35}$

2. The number of ordered pairs Neha can make from A to B

= n(A) × n(B)

= 5 × 7

= 35

3. The number of ordered pairs Neha can make from B to A

= n(B) × n(A)

= 7 × 5

= 35

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