Question

Neha swim 90 m long pool. She covers 180 m in one minute by swimming from one end to the other and back along the straight path. Find the average speed and average velocity of Neha?

Answer 1

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☞ Given :

Distance travelled in first lap = 90 meters

Distance travelled in second lap = 90 meters

Total distance = 180 meters

Time taken = 1 minute

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☆ Required to find :

1. Average speed
2. Average Velocity

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✎ Explanation :

In the question it is given that Neha is swimming in a long pool of 90 meters . She covers 180 meters in 1 minute . so he asked us to find average speed & average velocity .

we can find the average speed using a formula.

The formula is ;

$average \: speed \: = \frac{total \: distance}{total \: time \: taken}$

Hence, using this formula we can find the average speed.

Similarly;

To find average velocity we have to use the formula.

$average \: velocity \: = \frac{total \: displacement}{total \: time \: taken}$

Hence ; using this formula we can find average velocity .

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✐ Solution

Total distance = 180 meters

Total time taken = 1 minute

convert minutes into seconds

Hence;

1 minute = 60 seconds

Total time taken = 60 seconds

Therefore ;

averagespeed = total distance/ Total time taken

Hence ;

$average \: speed \: = \frac{180}{60} \\ \\ average \: speed \: = 3 \frac{m}{s}$

Therefore;

Average speed = 3 m/s .

Similarly ;

Total displacement = 0 meters

( this is because the object again reached it's initial position ) .

Total time taken = 60 seconds.

Average Velocity = Total displacement / Total time taken

Therefore;

$average \: velocity \: = \frac{0}{60} \\ \\ average \: velocity \: = 0 \frac{m}{s}$

Hence;

Average Velocity is 0 m/s .