Neha swims in a 100m long pool. She covers 200m in one minute and forty seconds by swimming from one end to the other and back along the same straight path .find average speed and average velocity of neha
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110
length of pool = 100m
total time taken = 1 min + 40s = 60s + 40s = 100s
total distance covered by Neha = 200m
therefore, the total displacement covered by Neha = 0m
[because she swims from one end of the pool to the other and back along the same straight path, to her original position.]
Now, According to the question-
average speed = total distance = 200 m = 2 m/s
total time taken 100 s
average velocity = total displacemet = 0 m = 0 m/s
total time taken 100 s
total time taken = 1 min + 40s = 60s + 40s = 100s
total distance covered by Neha = 200m
therefore, the total displacement covered by Neha = 0m
[because she swims from one end of the pool to the other and back along the same straight path, to her original position.]
Now, According to the question-
average speed = total distance = 200 m = 2 m/s
total time taken 100 s
average velocity = total displacemet = 0 m = 0 m/s
total time taken 100 s
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3
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