neha walks from her house 160m north and from there 630m west to visit her friends house. While coming back, she walks diagonally from her friends house to her house. how much distance does she covers while returning?
Answers
Answered by
15
While returning she covers 650 m.
By Pythagoras Theorem
AB^2+BC^2=AC^2
Here,
AB=160m
BC=630m
Therefore AC=Square root of AB^2+BC^2=650m
By Pythagoras Theorem
AB^2+BC^2=AC^2
Here,
AB=160m
BC=630m
Therefore AC=Square root of AB^2+BC^2=650m
Answered by
12
(h)^2=(b)^2+(p)^2
h^2=160^2 + 630^2
h^2=25600 +396900
h^2=422,500
h=√422500
h= 650
h^2=160^2 + 630^2
h^2=25600 +396900
h^2=422,500
h=√422500
h= 650
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